# A 10-M-Long Glider With A Mass Of 680 Kg (Including The Passengers) Is Gliding Horizontally Through The Air

A 10-m-long glider with a mass of 680 kg (including the passengers) is gliding horizontally through the air at 30 m/s when a 60 kg skydiver drops out by releasing his grip on the glider. What is the glider’s velocity just after the skydiver lets go?

**Known**:

𝑚_{𝑆} = 60 𝑘𝑔 (mass of skydiver)

𝑚_{𝐺}_{+}_{𝑆} = 680 𝑘𝑔 (mass of glider plus the mass of skydiver)

𝑚_{𝐺} = 𝑚_{𝐺}_{+}_{𝑆} − 𝑚_{𝑆} = 680 𝑘𝑔 – 60 𝑘𝑔 = 620 𝑘𝑔 (mass of glider)

𝑣_{𝐺𝑖} = 30 m/s

𝑚_{𝑆} = 60𝑘𝑔

** Note**: turns out as the skydiver releases, the skydiver’s
final velocity will be the same as glider’s initial velocity thus,

𝑣_{𝑆𝑓} = 𝑣_{𝐺i}

__Find:__

𝑣_{𝐺𝑓} =?

__SOLUTION:__

Using the Law of
Conservation of Momentum equation (𝑷𝒇 = 𝑷𝒊),

(𝑚_{𝐺})𝑣_{𝐺𝑓} + (𝑚_{𝑆})𝑣_{𝑆𝑓 }= (𝑚_{𝐺}_{+}_{𝑆})𝑣_{𝐺𝑖}

Substitute 𝑣_{𝐺𝑖}
for 𝑣_{𝑆f} given that 𝑣_{𝑆f} = 𝑣_{𝐺𝑖}, then solve for the gliders final velocity

(𝑚_{𝐺})𝑣_{𝐺𝑓} + (𝑚_{𝑆})𝑣_{𝐺𝑖}= (𝑚_{𝐺}_{+}_{𝑆})𝑣_{𝐺}_{i}

(m_{G})v_{Gf} = (m_{G+S})v_{Gi}
– (m_{S})v_{Gi}

v_{Gf} = (m_{G+S})v_{Gi} – (m_{S})v_{Gi}
/ (m_{G})

v_{Gf} = (680)30 – (60)30 / (620)

v_{Gf} = 30 m/s

**The ****glider’s**** ****velocity just after the
skydiver lets go****
is 30 m/s.**

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