-->

Sin a = 3/5 Dan Tan b = 12/5, Nilai cos (a + b) = ....


 JAWABAN: D

PEMBAHASAN:

sin a = 3/5, cos a = 4/5

tan b =12/5, sin b = 12/13, cos b = 5/13

cos (a + b) = cos a cos b – sin a sin b

cos (a + b) = 4/5 . 5/13 – 3/5 . 12/13

cos (a + b) = 4/13 – 36/65

cos (a + b) = 20/13 – 36/65

cos (a + b) = -16/65

0 Response to "Sin a = 3/5 Dan Tan b = 12/5, Nilai cos (a + b) = ...."

Post a Comment